The Soils used in this test are pulverized clay, the coefficient of internal resistance tanφ=0.74 φ=36°30′ and cohesion c=0.328kg/cm
2, and sandy' loam, the moisture contents are nearly 29% (w. b.), In these soils the farm wheel that has the lug which has 4 different angle is driven by the power. On this test the soil and wheel shaft are both fixed, then the slip percentage of it to the soil are all 100%.
The results are follows.
(1) It is confirmed that the sliding shear planes spring up in two directions which have the angle ±(π/4-φ/2) against the maximum principal stress.
(2) The primary shear plane of them formed the triangle with the wheel surface and that lug.
(3) As the area of that triangle increases with the wheel rotation, it is found that the direction of the principal stress is not followed the angle of lug.
(4) As this part works as the rigid body, they are considered as the one part of the wheel.
(5) Then, at first, the direction of the principal stress are effected by the lug angle,
(6) but, after that, it is not effected.
(7) Rather, it is effected by the sinking degree and slip percentage of the wheel.
(8) After, when the primary shear plane arrives to the soil surface, the resistance of the soil decreases immediately as fig. 6.
(9) The time of that is when the lug comes to the point before 20 degree from the vertical center line of wheel.
(10) As the coefficient of internal resistance and shearing resistance are small in the moistened soil by the great deal of water, the soil reaction force is small.
(11) The calculation of stress and the reaction force to the lug are described in IV, but the results of that will be published in next paper.
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