Methylolmelamine (MM) has a 1, 3, 5-triazine ring and three amino groups which are substituted by the methylol group. Therefore, MM acts as a proton donar and a proton acceptor on the hydrogen bond formation. In this paper the hydrogen bond formations between MM's were studied by the CNDO/2 method. In the present calculation, methanol was adopted for one of MM's in order to save the memory storage of computer and computing time, because the hydroxyl group of methanol is approximately equal to the methylol group of MM in hydrogen bonding strength. With respect to the hydrogen bond between MM and methanol N atom of MM ring plays an important role in hydrogen bond with methanol more than its methylol group. The hydrogen bonding strength of N atom of MM ring is enhanced by the adjacent amino groups, but at the same time is disturbed by the nearest neighbour methylol group substituted in the amino group.
Therefore, the hydrogen bond formation between N atom of MM ring and methnol was classified as the following three cases.
(1) The two H atoms at the 4- and 6-positions of the amino groups (refer to text) are free from the methylolization.
(2) One H atom at the 4- or 6-position is free from the methylolization.
(3) The two H atoms at the 4- and 6-positions are methylolized.
In the case (1), the stable hydrogen bond formation is possible and it gives the largest hydrogen bond energy among the three cases. In the case (2), the hydrogen bond formation depends on the configuration of the methylol group and methanol to avoid the steric hindrance between them. In the case (3), the hydrogen bond formation may be difficult. The hydrogen bond energy between methylol group and methanol is approximately equal to the hydrogen bond energy of methanol dimer. This result suggests that the methylol group of MM acts in the similar manner of the hydroxyl group of methanol in the hydrogen bond formation.
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