Examination was made on the reactivity of active methylene in asymmetric, straight-chain ketone of the formula R-CH
2COCH
2-R′, in the synthesis of 2-aminothiazole by reaction with thiourea and iodine, using a basic catalyst. Contrary to the use of an acid catalyst, the use of a basic catalyst was found to result in different reactivity of the methylene according to the nature of R and R′. When R is hydrogen and R′ is a straight-chain bond, the methylene on the side of R′-CH
2- is more reactive when the catalyst is a weak base, as in the case of an acid base, and both methyl and methylene react when the catalyst is a strong base, affording a mixture of the two kinds of product. However, CH
3CO(CH
2)
5CH
3 is an exception and its methyl group undergoes the reaction to form 2-amino-4-hexylthiazole. When the R′-CH
2- has a branched bond, chiefly the methylene undergoes the reactiton with a weak base and the methyl preferentially reacts when the catalyst is a strong acid. When R is a methyl and R′ is a straight-chain alkyl, the methylene of R′-CH
2-undergoes the reaction, but when R′ is a branched alkyl, the compound undergoes resinification and objective substance is not obtained.
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