Abstract
1-(Trifluoromethyl)-(1) and 2-(trifluoromethyl) naphthalene (2) were synthesized by the reaction of halogenonaphthalenes with trifluoromethyl iodide (3) in the presence of copper powder. Selection of the solvent was found to be important for increasing the yield of the desired product. In pyridine, the reaction of 2-iodonaphthalene with (3) afforded (2) in an excellent yield (86%), but in DMF, the yield of (2) was low (19%).
Similarly (1) was prepared by the reaction of 1-iodonaphthalene with (3) in a 63% yield. Activity of the halogenonaphthalenes decreased in the following order: iodonaphthalene>bromonaphthalene>>chloronaphthalene.
