Abstract
Novel oxyfluoride Bi2PdO4F0.5 was synthesized by anion intercalation. XRD pattern of the product could be indexed using the same space group (P4/ncc) as Bi2PdO4. Although Bi2PdO4 shows no magnetic moment, Curie-Weiss behavior was observed in fluorinated samples. The observed spin is probably derived from Pd ions. Palladium in an oxidation state between two and four tends to disproportionate into Pd2+ and Pd4+. Since Pd2+ and Pd4+ do not have spin, the observed spin moment in Bi2PdO4F0.5 means that the Pd ions are in a higher valence state, without such disproponation.