Abstract
The structure of N,N′-bis(3-nitroobenzylidene)butane-1,4-diamine was determine by X-ray crystallography. The symmetry operation (-x + 2, -y + 1, -z) generates the whole molecule. The compound crystallizes in a monoclinic system and was characterized thus: P21/c, a = 4.981(5), b = 11.205(7), c = 15.134(12)Å, β = 92.28(4)°, Z = 2, V = 843.9(12)Å3. The crystal structure was solved by direct methods and refined by full-matrix least-squares on F2 to final values of R = 0.0624 and wR = 0.1329.