2020 年 72 巻 3 号 p. 891-907
For knots in 𝑆3, it is well-known that the Alexander polynomial of a ribbon knot factorizes as 𝑓(𝑡)𝑓(𝑡−1) for some polynomial 𝑓(𝑡). By contrast, the Alexander polynomial of a ribbon 2-knot in 𝑆4 is not even symmetric in general. Via an alternative notion of ribbon 2-knots, we give a topological condition on a 2-knot that implies the factorization of the Alexander polynomial.
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