The most general form of the differential equation for the linear conduction of heat is given by
The solution of this equation with the conditons: can be obtained by the method given in my previous paper (2nd Series, Vol. 10, p. 507 of this Journal) in the form:
The same method can be applied to the case in which the conditions are given by
Since
K≠0 at both ends, μ
s can be determined from the equation
When
Zs(
x) satisfies the relations:
when
Zs(
s) is normalized, the solution is
The differential equation in the case of wind drift when the effect of floating ice pieces are taken into account must be solved under the boundary conditions:
This problem can be solved by the same method
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